From 83e85f6a0837c9cf39146c4798a8583aecba5da3 Mon Sep 17 00:00:00 2001
From: Mark Whitley <markw@lineo.com>
Date: Tue, 25 Jul 2000 20:48:44 +0000
Subject: Modified print_subst_w_backrefs() so it will print backslash escaped
characters properly, just like GNU sed.
---
editors/sed.c | 6 ++++++
sed.c | 6 ++++++
2 files changed, 12 insertions(+)
diff --git a/editors/sed.c b/editors/sed.c
index 69a5e0324..665471913 100644
--- a/editors/sed.c
+++ b/editors/sed.c
@@ -500,6 +500,12 @@ static void print_subst_w_backrefs(const char *line, const char *replace, regmat
fputc(line[j], stdout);
}
+ /* if we find a backslash escaped character, print the character */
+ else if (replace[i] == '\\') {
+ ++i;
+ fputc(replace[i], stdout);
+ }
+
/* if we find an unescaped '&' print out the whole matched text.
* fortunately, regmatch[0] contains the indicies to the whole matched
* expression (kinda seems like it was designed for just such a
diff --git a/sed.c b/sed.c
index 69a5e0324..665471913 100644
--- a/sed.c
+++ b/sed.c
@@ -500,6 +500,12 @@ static void print_subst_w_backrefs(const char *line, const char *replace, regmat
fputc(line[j], stdout);
}
+ /* if we find a backslash escaped character, print the character */
+ else if (replace[i] == '\\') {
+ ++i;
+ fputc(replace[i], stdout);
+ }
+
/* if we find an unescaped '&' print out the whole matched text.
* fortunately, regmatch[0] contains the indicies to the whole matched
* expression (kinda seems like it was designed for just such a
--
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