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1/* $OpenBSD: md5crypt.c,v 1.9 1997/07/23 20:58:27 kstailey Exp $ */
2
3/*
4 * ----------------------------------------------------------------------------
5 * "THE BEER-WARE LICENSE" (Revision 42):
6 * <phk@login.dknet.dk> wrote this file. As long as you retain this notice you
7 * can do whatever you want with this stuff. If we meet some day, and you think
8 * this stuff is worth it, you can buy me a beer in return. Poul-Henning Kamp
9 * ----------------------------------------------------------------------------
10 *
11 * $FreeBSD: crypt.c,v 1.5 1996/10/14 08:34:02 phk Exp $
12 *
13 */
14
15#if defined(LIBC_SCCS) && !defined(lint)
16static char rcsid[] = "$OpenBSD: md5crypt.c,v 1.9 1997/07/23 20:58:27 kstailey Exp $";
17#endif /* LIBC_SCCS and not lint */
18
19#include <unistd.h>
20#include <stdio.h>
21#include <string.h>
22#include <md5.h>
23#include <string.h>
24
25static unsigned char itoa64[] = /* 0 ... 63 => ascii - 64 */
26 "./0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz";
27
28static void to64 __P((char *, u_int32_t, int));
29
30static void
31to64(s, v, n)
32 char *s;
33 u_int32_t v;
34 int n;
35{
36 while (--n >= 0) {
37 *s++ = itoa64[v&0x3f];
38 v >>= 6;
39 }
40}
41
42/*
43 * UNIX password
44 *
45 * Use MD5 for what it is best at...
46 */
47
48char *
49md5crypt(pw, salt)
50 register const char *pw;
51 register const char *salt;
52{
53 /*
54 * This string is magic for this algorithm. Having
55 * it this way, we can get get better later on
56 */
57 static unsigned char *magic = (unsigned char *)"$1$";
58
59 static char passwd[120], *p;
60 static const unsigned char *sp,*ep;
61 unsigned char final[16];
62 int sl,pl,i;
63 MD5_CTX ctx,ctx1;
64 u_int32_t l;
65
66 /* Refine the Salt first */
67 sp = (const unsigned char *)salt;
68
69 /* If it starts with the magic string, then skip that */
70 if(!strncmp((const char *)sp,(const char *)magic,strlen((const char *)magic)))
71 sp += strlen((const char *)magic);
72
73 /* It stops at the first '$', max 8 chars */
74 for(ep=sp;*ep && *ep != '$' && ep < (sp+8);ep++)
75 continue;
76
77 /* get the length of the true salt */
78 sl = ep - sp;
79
80 MD5Init(&ctx);
81
82 /* The password first, since that is what is most unknown */
83 MD5Update(&ctx,(const unsigned char *)pw,strlen(pw));
84
85 /* Then our magic string */
86 MD5Update(&ctx,magic,strlen((const char *)magic));
87
88 /* Then the raw salt */
89 MD5Update(&ctx,sp,sl);
90
91 /* Then just as many characters of the MD5(pw,salt,pw) */
92 MD5Init(&ctx1);
93 MD5Update(&ctx1,(const unsigned char *)pw,strlen(pw));
94 MD5Update(&ctx1,sp,sl);
95 MD5Update(&ctx1,(const unsigned char *)pw,strlen(pw));
96 MD5Final(final,&ctx1);
97 for(pl = strlen(pw); pl > 0; pl -= 16)
98 MD5Update(&ctx,final,pl>16 ? 16 : pl);
99
100 /* Don't leave anything around in vm they could use. */
101 memset(final,0,sizeof final);
102
103 /* Then something really weird... */
104 for (i = strlen(pw); i ; i >>= 1)
105 if(i&1)
106 MD5Update(&ctx, final, 1);
107 else
108 MD5Update(&ctx, (const unsigned char *)pw, 1);
109
110 /* Now make the output string */
111 strcpy(passwd,(const char *)magic);
112 strncat(passwd,(const char *)sp,sl);
113 strcat(passwd,"$");
114
115 MD5Final(final,&ctx);
116
117 /*
118 * and now, just to make sure things don't run too fast
119 * On a 60 Mhz Pentium this takes 34 msec, so you would
120 * need 30 seconds to build a 1000 entry dictionary...
121 */
122 for(i=0;i<1000;i++) {
123 MD5Init(&ctx1);
124 if(i & 1)
125 MD5Update(&ctx1,(const unsigned char *)pw,strlen(pw));
126 else
127 MD5Update(&ctx1,final,16);
128
129 if(i % 3)
130 MD5Update(&ctx1,sp,sl);
131
132 if(i % 7)
133 MD5Update(&ctx1,(const unsigned char *)pw,strlen(pw));
134
135 if(i & 1)
136 MD5Update(&ctx1,final,16);
137 else
138 MD5Update(&ctx1,(const unsigned char *)pw,strlen(pw));
139 MD5Final(final,&ctx1);
140 }
141
142 p = passwd + strlen(passwd);
143
144 l = (final[ 0]<<16) | (final[ 6]<<8) | final[12]; to64(p,l,4); p += 4;
145 l = (final[ 1]<<16) | (final[ 7]<<8) | final[13]; to64(p,l,4); p += 4;
146 l = (final[ 2]<<16) | (final[ 8]<<8) | final[14]; to64(p,l,4); p += 4;
147 l = (final[ 3]<<16) | (final[ 9]<<8) | final[15]; to64(p,l,4); p += 4;
148 l = (final[ 4]<<16) | (final[10]<<8) | final[ 5]; to64(p,l,4); p += 4;
149 l = final[11] ; to64(p,l,2); p += 2;
150 *p = '\0';
151
152 /* Don't leave anything around in vm they could use. */
153 memset(final,0,sizeof final);
154
155 return passwd;
156}
157