Simplify utf8 helper function.

There's no need for `compat_utf8_escape()` to be a vararg function.
Remove default templates from `package.path`.

2 files changed, 2 insertions, 8 deletions

diff --git a/lprefix.h b/lprefix.h
index cba5bbc..9f970c4 100644
--- a/lprefix.h
+++ b/lprefix.h
@@ -51,16 +51,10 @@
 
 #ifdef lutf8lib_c
 #  define luaopen_utf8 luaopen_compat53_utf8
-#  include <stdarg.h>
 /* we don't support the %U format string of lua_pushfstring!
  * code below adapted from the Lua 5.3 sources:
  */
-static const char *compat53_utf8_escape (lua_State* L, ...) {
-  long x = 0;
-  va_list argp;
-  va_start(argp, L);
-  x = (long)va_arg(argp, long);
-  va_end(argp);
+static const char *compat53_utf8_escape (lua_State* L, long x) {
   if (x < 0x80) { /* ASCII */
     char c = (char)x;
     lua_pushlstring(L, &c, 1);
diff --git a/tests/test.lua b/tests/test.lua
index f2094b9..8adad1a 100755
--- a/tests/test.lua
+++ b/tests/test.lua
@@ -42,7 +42,7 @@ if arg[1] == "module" then
 end
 
 
-package.path = "../?.lua;../?/init.lua;"..package.path
+package.path = "../?.lua;../?/init.lua"
 package.cpath = "./?-"..V..".so;./?-"..V..".dll;./?.so;./?.dll"
 if mode == "module" then
   print("testing Lua API using `compat53.module` ...")