lua_call cannot be a macro, because it would push the function

over the parameters

1 files changed, 2 insertions, 3 deletions

diff --git a/lua.h b/lua.h
index 2a9e30b3..f53c091d 100644
--- a/lua.h
+++ b/lua.h
@@ -2,7 +2,7 @@
 ** LUA - Linguagem para Usuarios de Aplicacao
 ** Grupo de Tecnologia em Computacao Grafica
 ** TeCGraf - PUC-Rio
-** $Id: lua.h,v 3.4 1994/11/07 18:27:39 roberto Exp roberto $
+** $Id: lua.h,v 3.5 1994/11/08 19:56:39 roberto Exp roberto $
 */
 
 
@@ -35,6 +35,7 @@ void           lua_error		(char *s);
 int            lua_dofile               (char *filename);
 int            lua_dostring             (char *string);
 int            lua_callfunction         (lua_Object function);
+int            lua_call                 (char *funcname);
 
 lua_Object     lua_getparam             (int number);
 #define        lua_getresult            lua_getparam
@@ -69,8 +70,6 @@ void	       lua_unlock		(int ref);
 
 #define lua_register(n,f)       (lua_pushcfunction(f), lua_storeglobal(n))
 
-#define lua_call(f)           lua_callfunction(lua_getglobal(f))
-
 #define lua_getindexed(o,n) (lua_pushobject(o), lua_pushnumber(n), lua_getsubscript())
 #define lua_getfield(o,f)   (lua_pushobject(o), lua_pushstring(f), lua_getsubscript())