Remove support for big-endian i386 and amd64.

Before someone suggests the OpenSSL people are junkies, here is what they
mention about this:
	/* Most will argue that x86_64 is always little-endian. Well,
	 * yes, but then we have stratus.com who has modified gcc to
	 * "emulate" big-endian on x86. Is there evidence that they
	 * [or somebody else] won't do same for x86_64? Naturally no.
	 * And this line is waiting ready for that brave soul:-) */

So, yes, they are on drugs. But they are not alone, the stratus.com people are,
too.

1 files changed, 1 insertions, 7 deletions

diff --git a/src/lib/libcrypto/sha/sha512.c b/src/lib/libcrypto/sha/sha512.c
index 50c229ddeb..32bfecbf9b 100644
--- a/src/lib/libcrypto/sha/sha512.c
+++ b/src/lib/libcrypto/sha/sha512.c
@@ -318,13 +318,11 @@ static const SHA_LONG64 K512[80] = {
                                 : "=r"(ret)             \
                                 : "J"(n),"0"(a)         \
                                 : "cc"); ret;           })
-#   if !defined(B_ENDIAN)
 #    define PULL64(x) ({ SHA_LONG64 ret=*((const SHA_LONG64 *)(&(x)));  \
                                 asm ("bswapq    %0"             \
                                 : "=r"(ret)                     \
                                 : "0"(ret)); ret;               })
-#   endif
-#  elif (defined(__i386) || defined(__i386__)) && !defined(B_ENDIAN)
+#  elif (defined(__i386) || defined(__i386__))
 #   if defined(I386_ONLY)
 #    define PULL64(x) ({ const unsigned int *p=(const unsigned int *)(&(x));\
                          unsigned int hi=p[0],lo=p[1];          \
@@ -421,11 +419,7 @@ static void sha512_block_data_order (SHA512_CTX *ctx, const void *in, size_t num
 
         for (i=0;i<16;i++,F--)
                 {
-#ifdef B_ENDIAN
-                T = W[i];
-#else
                 T = PULL64(W[i]);
-#endif
                 F[0] = A;
                 F[4] = E;
                 F[8] = T;